Find the least value of 7a for which at least one of the roots of the equation x 2 – (a – 3) x + a = 0 is greater than 2.
Text Solution
Verified by Experts63
(63)
Sol. case- I: Both roots are greater than 2.
or one root is 2 & other is greater than 2
D
0
⇒ (a – 3) 2 – 4a
0
⇒ a 2 – 10 a + 9
0
(a – 1) (a – 9)
0
a ∈ (– ∞ , 1] ∪ [9, ∞ ) ... (i)
⇒
> 2
⇒ a > 7 ... (ii)
f(2)
0 ⇒ 4 – 2(a – 3) + a
0
– a + 10
0 ⇒ a
10... (iii)
(i) ∩ (ii) ∩ (iii) gives is
a ∈ [9, 10] ... (iv)


Case-II: One root is greater than 2
f(2) < 0 ⇒ – a + 10 < 0
⇒ a > 10 ⇒ a ∈ (10, ∞ )....(v)
(iv) ∪ (v) gives final answer as
a ∈ [9, ∞ )
Least value of 7a is 63.

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